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#include <iostream>
#include <initializer_list>
#include <array>
#include <iterator>
#include <algorithm>
 
 
void InitializerWork ( std::initializer_list<int> arginit ) {
    for ( auto ip = arginit.begin(); ip != arginit.end(); ++ip ) {
        std::cout << *ip << std::endl; 
    }
    std::cout << "So that's an initializer_list..." << std::endl;
}
 
template<typename TDesired, typename T, std::size_t n>
void GetArg ( const std::array<T, n> table, std::size_t& idx, const T& arg ) {
    table[idx++] = &arg;
}
 
template <typename ...Args>
void VariadicWork ( Args... args ) {
    std::array<const int*, sizeof...(args)> argtable;
    std::size_t index = 0;
    // ... What do?
    GetArg<int>( &argtable, index, args... );
    for ( auto ip = argtable.begin(); ip != argtable.end() ++ip ) {
        std::cout << *ip << std::endl;
    }
    std::cout << "That's... everything, I think." << std::endl;
}
 
 
int main (int argc, char* argv[]) {
 
    InitializerWork( { 20, 40, 80 } );
    VariadicWork( 20, 40, 80 );
 
}

prog.cpp: In function 'void VariadicWork(Args ...)':
prog.cpp:26:62: error: expected ';' before 'ip'
prog.cpp: In function 'void VariadicWork(Args ...) [with Args = {int, int, int}]':
prog.cpp:36:30:   instantiated from here
prog.cpp:25:5: error: no matching function for call to 'GetArg(std::array<const int*, 3u>*, size_t&, int&, int&, int&)'
prog.cpp:36:30:   instantiated from here
prog.cpp:26:36: error: lvalue required as increment operand

Standard output is empty